-48x^2+192x=0

Solution for -48x^2+192x=0 equation:

-48x^2+192x=0

a = -48; b = 192; c = 0;
Δ = b2-4ac
Δ = 1922-4·(-48)·0
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(192)-192}{2*-48}=\frac{-384}{-96}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(192)+192}{2*-48}=\frac{0}{-96}
=0
$